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A puck of mass 0.150 kg is moving on a frictionless, horizontal air track with a speed of 0.9m/s. It has a head-on collision with another puck of mass 0.300 kg that is moving to the left with a speed of 2.2m/s. Find the final velocity (magnitude and direction) of each glider if the collision is elastic.

Respuesta :

lcmendozaf

Answer:

V1f = 3.23 m/s in the direction of the 2nd puck

V2f = 0.13 m/s in the same direction it was moving

Explanation:

These are our given data:

V1o = 0.9 m/s      m1 = 0.150 kg

V2o = -2.2 m/s    m2 = 0.300 kg

Using the equations for elastic collisions:

[tex]V1f = \frac{m1-m2}{m1+m2} *V1o+\frac{2*m2}{m1+m2}*V2o=-3.23m/s[/tex]

[tex]V2f = \frac{2*m1}{m1+m2} *V1o+\frac{m2-m1}{m1+m2}*V2o=-0.13m/s[/tex]

They both move in the same direction as the 2dn puck was moving.

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