Answer:
349.07 N
Explanation:
Inlet area, [tex]A_i=\frac {\pi (d_i)^{2}}{4}=\frac {\pi \times 0.25^{2}}{4}= 0.049087 m^{2}[/tex]
Outlet area, [tex]A_o=\frac {\pi (d_o)^{2}-(d_i)^{2}}{4}=\frac {\pi \times 0.25^{2}-0.2^{2}}{4}= 0.017671 m^{2}[/tex]
[tex]A_iV_i=A_oV_o[/tex]
0.049087*2=0.017671v_o[/tex]
[tex]v_o=\frac {0.049087*2}{0.017671}=5.555556 m/s[/tex]
Mass flow rate=[tex]\rhoA_iV_i=1000*0.049087*2=98.17477 Kg/s[/tex]
[tex]F_x=98.17477(v_o-v_i)= 98.17477(5.555556-2)= 349.0659 N\approx 349.07 N[/tex]