Answer:
F = 1142.28 N
Explanation:
It is given that,
Radius of the cylinder, r = 6 cm = 0.06 m
Pressure of the surrounding air, [tex]P=1.01\times 10^5\ Pa[/tex]
Let F the minimum force required to remove the lid from the top of the cylinder. We know that the force acting per unit area is called pressure exerted. Its formula is given by :
[tex]P=\dfrac{F}{A}[/tex]
[tex]F=P\times A[/tex]
[tex]F=P\times \pi r^2[/tex]
[tex]F=1.01\times 10^5\ Pa\times \pi (0.06)^2[/tex]
F = 1142.28 N
So, the minimum force required to remove the lid from the top of the cylinder is 1142.28 N. Hence, this is the required solution.
The minimum force required to remove the lid from the top of the cylinder is 1142.28 N.
This is defined as the force applied is perpendicular to the surface of objects per unit area.
Radius of the cylinder, r = 6 cm = 0.06 m
Pressure of the surrounding air = 1.01 × 10⁵ Pa
Pressure = Force/Area
Force = Pressure × Area
= 1.01 × 10⁵ Pa × π (0.06)²
= 1142.28 N.
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