Answer:
h = 206.4 m
range = 515.9 m
Explanation:
from the question we are given the following:
initial velocity (u) = 75 m/s
angle above surface = 58 degrees
acceleration due to gravity (g) = 9.8 m/s^{2}
find the maximum height (h) and the horizontal distance
maximum height (h) = [tex]\frac{u^{2}sinθ^{2} }{2g}[/tex]
h = [tex]\frac{75^{2}sin58^{2} }{2 x 9.8}[/tex]
h = 206.4 m
the horizontal distance here is the range
range = [tex]\frac{u^{2}sin2θ }{g}[/tex]
range = [tex]\frac{75^{2}sin(2 x 58) }{9.8}[/tex]
range = 515.9 m
