Answer:
The maximum efficiency possible of such a heat engine is 8.9%.
Explanation:
Given that,
High temperature = 30°C
Depth = 1200 m
low temperature = 3°C
We need to calculate the maximum efficiency
Using formula of efficiency
[tex]e=1-\dfrac{T_{l}}{T_{h}}[/tex]
Where, [tex]T_{l}[/tex] = low temperature
[tex]T_{h}[/tex] =High temperature
Put the value into the formula
[tex]e=1-\dfrac{3+273}{30+273}[/tex]
[tex]e=0.089[/tex]
The efficiency in percentage,
[tex]e=0.089\times100[/tex]
[tex]e=8.9\%[/tex]
Hence, The maximum efficiency possible of such a heat engine is 8.9%.