0.4825 moles of O₂
Explanation:
We have the following chemical reaction in which sodium (Na) reacts with oxygen (O₂) to produce sodium oxide (Na₂O):
4 Na + O₂ → 2 Na₂O
number of moles = mass / molecular weight
number of moles of Na = 45.2 / 23 = 1.97 moles
Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:
if 4 moles of Na react with 1 mole of O₂
then 1.97 moles of Na react with X moles of O₂
X = (1.93 × 1) / 4 = 0.4825 moles of O₂
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