Answer: b) closer to F because fluorine has a higher electronegativity than hydrogen.
Explanation:
Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself.
A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.
Non-polar covalent bond is defined as the bond which is formed when there is no difference of electronegativities between the atoms.
electronegativity of flourine = 3.98
electronegativity of hydrogen = 2.1
As electronegativity of flourine is greater than that of electronegativity of hydrogen, the electron pair lie towards flourine , thus creating a partial negative charge on flourine and a partial positive charge on hydrogen.
The electron pair in a H-F bond could be considered closer to F because fluorine has a higher electronegativity than hydrogen.
Electronegativity refers to the property of an element to attract a shared pair of electron towards itself.
Normally, the electronegativity of flourine is 3.98 while the electronegativity of hydrogen is 2.1.
Hence, as the electronegativity of flourine is greater than electronegativity of hydrogen, the electron pair lie towards flourine and thus creates a partial negative charge on flourine and a partial positive charge on hydrogen.
Therefore, the Option B is correct.
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