Answer:
(a) 122.5 joule
(b) 122.5 joule
(c) 2722.2 N/m
Explanation:
we are given the following:
mass of block (m) = 5 kg
height above the spring (h) = 2.2 m
compression = 30 cm = 0.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(a) Find the gravitational potential energy (GPE)
GPE = m x g x h
where h is the addition of the compression and the height above the spring
h = 2.2 + 0.3 = 2.5 m
GPE = 5 x 9.8 x 2.5 = 122.5 joule
(b) find the energy stored when the spring comes to a halt (ES)
When the mass comes to a halt, the spring potential energy is equal to the gravitational potential energy.
therefore the energy stored in a spring = 122.5 joule
(c) find the spring constant
potential energy in a spring = 0.5 x k x X^{2}
where K is the spring constant
122.5 = 0.5 x K x 0.3^{2}
K = 2722.2 N/m
