Answer:
b: There are no zeros
Step-by-step explanation:
y = x² + 4x + 5
The parabola opens upward, because the coefficient of x² is positive.
Thus, the vertex is a minimum.
a = 1; b = 4; c = 5
The vertex form of a parabola is
y = (x - h)² + k
where (h, k) is the vertex and
h = -b/(2a) and k = f(h)
[tex]h = -\dfrac{4}{2\times1} = -\dfrac{4}{2} = -2[/tex]
k = f(2) = (-2)² + 4(-2) + 5 = 4 - 8 + 5 = 1
The vertex is at (-2, 1).
The parabola never reaches the x-axis, so there are no zeros.
The graph below shows that your parabola has no real zeros.
