When viewing a piece of art that is behind glass, one often is affected by the light that is reflected off the front of the glass (called glare), which can make it difficult to see the art clearly. One solution is to coat the outer surface of the glass with a thin film to cancel part of the glare.A) If the glass has a refractive index of 1.59 and you use , which has an index of refraction of 2.62, as the coating, what is the minimum film thickness that will cancel light of wavelength 560 nm?Answer is 107 nmB) If this coating is too thin to stand up to wear, what other thicknesses would also work? Find only the three thinnest ones.

Question

contestada

Respuesta :

boffeemadrid boffeemadrid · Answer 1 · 2019-11-18T09:10:12+01:00

Answer:

106.87022 nm

213.74045 nm, 320.61068 nm and 427.48091 nm

Explanation:

The light rays will only experience one reversal as the refractive index of the material is greater than glass.

For this case the destructive interference is given by

[tex]2nt=m\lambda\\\Rightarrow t=\frac{m\lambda}{2n}[/tex]

At m = 1 we will get minimum thickness

[tex]t=\frac{1\times 560}{2\times 2.62}\\\Rightarrow t=106.87022\ nm[/tex]

Minimum film thickness that will cancel light is 106.87022 nm

At m = 2

[tex]t=\frac{2\times 560}{2\times 2.62}\\\Rightarrow t=213.74045\ nm[/tex]

At m = 3

[tex]t=\frac{3\times 560}{2\times 2.62}\\\Rightarrow t=320.61068\ nm[/tex]

At m = 4

[tex]t=\frac{4\times 560}{2\times 2.62}\\\Rightarrow t=427.48091\ nm[/tex]

The three thinest coatings are 213.74045 nm, 320.61068 nm and 427.48091 nm