On a test flight, a rocket with mass 400 kg blasts off from the surface of the earth. The rocket engines apply a constant upward force F until the rocket reaches a height of 100 m and then they shut off. If the rocket is to reach a maximum height of 400 m above the surface of the earth, what value of F is required? Assume the change in the rocket's mass is negligible.

Respuesta :

Answer:F=11.76 kN

Explanation:

Given

mass of rocket [tex]m=400 kg[/tex]

Force F is applied up to a height of 100 m then it is shut off

final velocity v up to which force is applied is given by

[tex]v^2-u^2=2 as [/tex]

[tex]v^2-0=2\times a\times 100[/tex]

[tex]v=\sqrt{200 a}[/tex]

After this rocket continues to move to a maximum height under the action of gravity

using

[tex]v_1^2-v^2=2 gs_2[/tex]

[tex]s_2=400-100=300 m[/tex]

[tex]0-200 a=-2\times 9.8\times 300[/tex]

[tex]a=3 g=3\times 9.8=29.4 m/s^2[/tex]

thus Force is [tex]F=ma[/tex]

[tex]F=400\times 29.4=11,760=11.76 kN[/tex]

If the rocket is to reach a maximum height of 400 m above the surface of the earth, the value of Force will be 11.76kN.

Acceleration:

It is the rate at which velocity changes with time, in terms of both speed and direction.

  • The value of F is 11.76 kN.

Let's solve this question:

Given:

Mass of rocket , m=400kg

Force F is applied up to a height of 100 m then it is shut off.

  • Final velocity v up to which force is applied is given by:

[tex]v^2-u^2=2as\\\\v^2-0=2as\\\\v=\sqrt{2as}\\\\v=\sqrt{200a}[/tex]

  • After this rocket continues to move to a maximum height under the action of gravity.

[tex]v_1^2-v^2=2gs_2\\\\s_2=400-100=300m\\\\0-200a=-2*9.8*300\\\\a=3g=3*9.8=29.4m/s^2\\\\[/tex]

We know, Force is defined as the product of mass and acceleration.

[tex]\text{Force}= m*a\\\\\text{Force}=400*29.4\\\\\text{Force}=11760N=11.76kN[/tex]

Thus, the value of Force will be 11.76kN.

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