Answer
given,
100 km north in 20 min
50 km west in 40 min
500 km south in 52 min.
a) total distance
D = d₁ + d₂ + d₃
D = 100 + 150 + 500
D = 750 Km
displacement of the plane from the original position
[tex]D' = \sqrt{400^2 + 150^2}[/tex]
[tex]D' = \sqrt{160000 + 22500}[/tex]
[tex]D' = \sqrt{182500}[/tex]
D' = 427.2 Km
b) average speed
[tex]s = \dfrac{100 + 150 + 500}{20+40+52}[/tex]
[tex]s = \dfrac{750}{112}[/tex]
s = 6.696 km/minute
average velocity
[tex]s = \dfrac{total\ displacement }{\Delta t}[/tex]
[tex]s = \dfrac{427.2}{112}[/tex]
s = 3.814 km/minutes
