Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal molar concentrations of each solution, which member of each pair would theoretically be the better conductor of electricity? CsCl, CaCl2 CaS, Li2S KBr, AlCl3 AlCl3, MgC2 KI, K2S

Respuesta :

Answer:

CsCl, CaCl2 CaS, Li2S KBr, AlCl3 AlCl3, MgCl2 KI, K2S

Explanation:

For each pair I've made the answer bold. The explanation is simple. The more ions produce a salt after dissociation the more conductive will be solution (because you end up with more charged particles to transfer electricity).

Answer: Pairs CsCl, [tex]CaCl_{2}[/tex] CaS, [tex]Li_{2}S[/tex] KBr, [tex]AlCl_{3}[/tex], [tex]MgCl_{2}[/tex] KI, and [tex]K_{2}S[/tex] would theoretically be the better conductor of electricity.

Explanation:

Ionic compounds are the compounds which are readily soluble in polar solvents like water. When an ionic compound is dissolved in water then it dissociates into ions.

As electricity is the flow of ions or electrons. Therefore, ionic solutions are able to conduct heat and electricity.

For example, CsCl, [tex]CaCl_{2}[/tex] CaS, [tex]Li_{2}S[/tex] KBr, [tex]AlCl_{3}[/tex], [tex]MgCl_{2}[/tex] KI, and [tex]K_{2}S[/tex] are all ionic compounds.

Generally, an ionic compound is formed when a metal and a non-metal chemically combines with each other.

Thus, we can conclude that pairs CsCl, [tex]CaCl_{2}[/tex] CaS, [tex]Li_{2}S[/tex] KBr, [tex]AlCl_{3}[/tex], [tex]MgCl_{2}[/tex] KI, and [tex]K_{2}S[/tex] would theoretically be the better conductor of electricity.