Answer:
2/5
Step-by-step explanation:
Given Marcellus drank 1/4 gallon of the limeade and Marcy drank 1/8 gallon of the limeade
Given that only 5/8 portion of the pitcher contains limeade
Total amount drunk = amount drunk by Marcellus + amount drunk by Marcy
Total amount drunk = [tex]\frac{1}{4} +\frac{1}{8}[/tex] = [tex]\frac{3}{8}[/tex]
The amount of Limeade remained = The amount initially - the amount drunk
The amount remained = [tex]\frac{5}{8} -\frac{3}{8}[/tex] = [tex]\frac{1}{4}[/tex]
Fractional part = amount remained / amount initially = [tex]\frac{\frac{1}{4} }{\frac{5}{8} }[/tex] = [tex]\frac{2}{5}[/tex]
