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2FePO, + 3Na S0,
Fe (SO); + 2Na3PO4
What is the theoretical yield of Fe (SO2), it 20,00 g of Fepo, reacts with an excess of Na SO,?
26.52 g
53.04 g
150.8 g
399.99

Respuesta :

cristisp93

26.5 g of Fe₂(SO₄)₃

Explanation:

We have the following chemical reaction:

2 FePO₄ + 3 Na₂SO₄ → Fe₂(SO₄)₃ + 2 Na₃PO₄

number of moles = mass / molecular wight

number of moles of FePO₄ = 20 / 151 = 0.1325 moles

Taking in account the chemical reaction we devise the following reasoning:

if        2 moles of FePO₄ produces 1 mole of Fe₂(SO₄)₃

then  0.1325 moles of FePO₄ produces X moles of Fe₂(SO₄)₃

X = (0.1325 × 1) / 2 = 0.06625 moles of Fe₂(SO₄)₃

mass = number of moles × molecular wight

mass of Fe₂(SO₄)₃ = 0.06625 × 400 = 26.5 g

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number of  moles

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