Answer:
(a) 8.68 m/sec
(b) 472.22 m/sec
Explanation:
We have given that length of the rod l = 0.240 m
(a) We have given force F = 0.05 N
Resistance R = 10 ohm
Magnetic field B = 1 Tesla
We have to find the terminal velocity
We know that terminal velocity is given by
[tex]v_t=\frac{F R}{B^2l^2}[/tex] ,here F is force, R is resistance B is magnetic field and l is length of the rod
So [tex]v_t=\frac{0.05\times 10}{1^2\times 0.240^2}=8.68m/sec[/tex]
(b) Applied force F = 2.72 N
Resistance R = 10 ohm
Magnetic field B = 1 Tesla
We know that terminal velocity is given by
[tex]v_t=\frac{F R}{B^2l^2}[/tex] ,here F is force, R is resistance B is magnetic field and l is length of the rod
So [tex]v_t=\frac{2.72\times 10}{1^2\times 0.240^2}=472.22m/sec[/tex]