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At 1000°C and a pressure of 1200 mm Hg, a sample of methane occupies 20.0 L. What will be it's temperature if it is compressed to a volume of 4.00 L and a pressure of 3600 mm Hg?

Respuesta :

MathPhys

Answer:

491°C

Explanation:

Ideal gas law:

PV = nRT

If n is constant:

PV / T = PV / T

(1200 mmHg) (20.0 L) / (1273 K) = (3600 mmHg) (4.00 L) / T

T = 764 K

T = 491°C

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