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Find the product of each sum and difference. (2l + 9)(2l – 9)

(a) 4l2 + 18l – 81

(b) 4l2 – 81

(c) 4l2 + 81

(d) 4l

Respuesta :

Answer:(b). 4I2-81

Step-by-step explanation:(2I+9)(2I-9)

=4I2-18I+18I-81

=4I2-81

Answer:

Option c [tex]4l^2-81[/tex]

Explanation:

As we have given in the question  

[tex]Sum=(2l+9)\times(2l-9)[/tex]

So by using the formula

[tex](a-b) (a+b) = a^2+ab-ba-b^2[/tex]

So the equation will become

[tex](a+b)(a-b)=a^2-b^2[/tex]

So according to question,  we have ,

a = 2l and b = 9

So,

[tex](2l+9)(2l-9)=(4l^2-81)[/tex]

And required Sum=[tex](4l^2-81)[/tex]

So the final answer of the question which is required is  Sum=[tex](4l^2-81)[/tex]