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Electrical systems are governed by​ Ohm's law, which states that Vequals​IR, where Vequals​voltage, Iequals​current, and Requalsresistance. If the current in an electrical system is decreasing at a rate of 6 ​A/s while the voltage remains constant at 12 ​V, at what rate is the resistance increasing when the current is 20 ​A?

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Akinny

Answer:

0.09Ω/s

Step-by-step explanation:

V=IR

12 = 20 R

R = 12/20

  =   0.6 ohm

dI/dt (R) + dR/dt (I) =0

-6 x 0.6 + (dR/dt) x 40 =0

40(dR/dt)  =3.6

dR/dt =  3.6/40

         = 0.09Ω/s

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