Answer:
Number of electrons = 118
Electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶
Explanation:
Given: A chemical element that has completely filled 7p orbital.
According to this, the principal occupied electron shell or the valence shell of such an element is 7p.
⇒ the principal quantum number (n) for the valence shell is 7.
∴ this element belongs to the period 7 of the periodic table.
Also, an element that has completely filled p-orbital belongs to the group 18 of the p-block.
Therefore, an element that belongs to the group 7 and period 18 of the periodic table, should have a completely filled 5f, 6d, 7s and 7p orbitals.
Therefore, the electronic configuration should be: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶
And, the number of electrons = atomic number of radon (Rn) + 14 + 10 + 2 + 6 = 86 + 32 = 118.
Therefore, the given element has atomic number 118 and has the electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶. Thus the given element can be Oganesson.
