Answer:0.27
Explanation:
Given
One worker Pushes with force [tex]F_1=430 N[/tex]
other Pulls it with a rope of rope [tex]F_2=360 N[/tex]
mass of crate [tex]m=290 kg[/tex]
both forces are horizontal and crate slides with a constant speed
Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it
[tex]f_r=F_1+F_2[/tex]
where [tex]f_r[/tex] is the friction force
[tex]f_r=430+360 [/tex]
[tex]f_r=790 N[/tex]
[tex]f_r=\mu N[/tex]
where [tex]\mu [/tex]is the coefficient of static friction
[tex]N=mg[/tex]
[tex]790=\mu 29\cdot 9.8[/tex]
[tex]\mu =0.27[/tex]
