The oxidation number of I (iodine) decreases the in the described chemical reaction from 0 to -1.
Explanation:
We have the following chemical reaction:
I₂ + 2 KCl → KI + Cl₂
The following atoms have a change in the oxidation number:
I with a 0 oxidation number (in I₂) goes to I with -1 oxidation number (in KI) by receiving 1 electron.
Cl with a -1 oxidation number (in KCl) goes to I with 0 oxidation number (in Cl₂) by losing 1 electron.
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oxidation number
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