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A projectile is launched from a point on level ground with initial speed 7.1 miles/hour and initial angle of 6 degrees above the horizontal. Air resistance may be ignored and normal earth gravity is present. Calculate the final value of the horizontal component of velocity in m/s just prior to the projectile striking the ground. [Note: Don't forget to convert units as needed.] g

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Answer:

Final value of horizontal component velocity will be -3.11 m/sec        

Explanation:

We have given initial velocity of the projectile u = 7.1 miles/hour

We know that 1 miles = 1609 m

Angle of projection [tex]\Theta =6^{\circ}[/tex]

And 1 hour = 3600 sec

So [tex]7.1miles/hour=\frac{7\times 1609m}{3600sec}=3.128m/sec[/tex]

Now initial value of horizontal component [tex]u_{xi}=ucos\Theta =3.128cos6=3.11m/sec[/tex]

Now final value of horizontal component [tex]u_{xf}==-u_{xi}=-3.11m/sec[/tex]

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