Answer:
0.0071g
Explanation:
From the question, we know that the molarity of the BaCl2 is 0.00237M. This means there are 0.00237 moles in 1dm^3 or 1000cm^3 of solution.
We also know that 35ml of the BaCl2 reacted. Here, we need to calculate the number of moles in 35.7ml of BaCl2.
This is calculated as follows;
0.00237moles are in 1000cm^3
Thus x moles will be present in 35ml ( we should note that cm^3 is same as ml)
X = (0.00237 × 35) ÷ 1000 = 0.00008295 moles.
From the reaction equation, we can see that 2 moles of BaCl2 yielded 1 mole of Ba(OH)2.
This means 0.00008295mole of BaCl2 will yield 0.00008295 ÷ 2 = 0.000041475 moles of Ba(OH)2.
To calculate the mass of Ba(OH)2 formed, we simple multiply the number of moles yielded by the molar mass of Ba(OH)2.
Molar mass of Ba(OH)2 = 137 + 2(17)
= 171g/mol
Mass = 171 × 0.000041475 = 0.007092225g
