Answer:
50 N/m
Explanation:
The period is:
T = 5.0 s / 30
T = 0.167 s
The frequency is:
f = 1 / T
f = 6.0 Hz
The angular frequency is:
ω = 2πf
ω = 37.7 rad/s
Finding the spring constant:
ω = √(k / m)
k = ω² m
k = (37.7 rad/s)² (0.035 kg)
k = 49.7 N/m
Rounding, the spring constant is 50 N/m.
