Answer:
[tex]\frac{x+12}{4(x+3)}[/tex]
Step-by-step explanation:
we have
[tex](\frac{3}{x} +\frac{1}{4}):(1+\frac{3}{x})[/tex]
Multiply by 4x numerator and denominator to remove the fractions
[tex](\frac{3}{x}(4x) +\frac{1}{4}(4x)):(1(4x)+\frac{3}{x}(4x))[/tex]
[tex]\frac{12+x}{4x+12}[/tex]
Factor 4 in the denominator
[tex]\frac{x+12}{4(x+3)}[/tex]
