Answer:
[tex]24.22^{\circ}[/tex]
Explanation:
Given information
L = 250 m
e = 40 V
[tex]B = 5\times 10^{-5}[/tex]
[tex]v = 7.8\times 10^{3}m/s[/tex]
From emf equation
[tex]e=BLvsin \theta[/tex] and making [tex]\theta[/tex] the subject of the formula we have
[tex]sin\theta=\frac {e}{BLv}[/tex]
[tex]\theta=sin^{-1}(\frac {e}{BLv})[/tex]
And by substitution
[tex]\theta= sin^{-1}(\frac {40}{(5*10^{-5})\times 250 \times (7.8*10^{3})})=sin^{-1}(\frac {40}{97.5})= sin^{-1}0.4102564=24.22^{\circ}[/tex]