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Janell is standing on a set of bleachers and throws a ball into the air at an initial velocity of



35 ft/s. The height of the ball, h, at 1 seconds is modeled by the equation h = -162 +35t + 6



How many seconds will it take the ball to reach the ground

Respuesta :

Answer:

The time taken to reach ground is 3.45 sec

Step-by-step explanation:

Given as :

Distance of ball = h = -162 + 35t + 6  at t = 1 sec

The speed of ball thrown  = 35 ft per sec

Let the Time taken to reach ground = T sec

So Time = [tex]\frac{Distance}{Speed}[/tex]

Or, Time = [tex]\frac{-162+35t+6}{35}[/tex]

Now distance h at t= 1 sec ,

h = -162 + 35t +6

or,   h = - 162 + 35(1) + 6

So,  h = - 121  feet

Or   [tex]\begin{vmatrix}h\end{vmatrix}[/tex] = 121 feet

Or, Time = [tex]\frac{ 121}{35}[/tex]

Or,  Time = 3.45 sec

Hence The time taken to reach ground is 3.45 sec  Answer

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