Answer:
There are 342 g/ 95. 2 g/m = 3.59 moles
Explanation:
MgCl2 → Molar mass is 95.2g g/m
This is the mass in one mol so to find out the moles in 342g we have to divide the mass between the molar mass.
342 g/ 95. 2 g/m = 3.59 moles
Answer:
3.6 moles of [tex]MgCl_2[/tex] are present in 342 g of [tex]MgCl_2[/tex]
Explanation:
Given the weight of compound [tex]MgCl_2[/tex] = 342 g
Atomic Mass of Mg = 24 amu
Atomic Mass of Cl = 35.5 amu
Computing the molar mass of [tex]MgCl_2[/tex] = [tex](1 * 24)+(2 * 35.5)[/tex]amu = 24 + 71 = 95 amu
No. of moles of a compound is calculated by the formula = [tex]\frac{\text { Weight }}{\text { Molar Mass }}[/tex]
Substituting the value,
Moles = [tex]\frac{342}{95}=3.6 \mathrm{mol}[/tex]
Therefore, 3.6 moles of [tex]MgCl_2[/tex] are present in 342 g of [tex]MgCl_2[/tex]
