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A car whose total mass is 800kg travelling with a uniform velocity of 20m/s suddenly observes a stationary dog 50m ahead on its path. If the total force applied on the braking system on the car by the driver is 2000N, what would happen? ​

Respuesta :

opudodennis

Answer:

The driver hits the stationery dog because the applied force is less than required force

Explanation:

Kinetic energy will be given by

[tex]KE=0.5mv^{2}[/tex] where m is the mass of the vehicle and v is the speed/velocity of the vehicle.

Substituting 800 Kg for m and 20 m/s for v we obtain

[tex]KE=0.5*800*(20 m/s)^{2}=160,000[/tex]

Frictional force by vehicle pads is given by

[tex]Fr=\frac {KE}{d}[/tex] where d is the distance moved

Substituting 160000 for KE and 50 m for d we obtain

[tex]Fr=\frac {160000}{50}=3200 N[/tex]

Therefore, the vehicle hits the dog since the required force is 3200N but the driver applied only 2000 N

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