The object takes 8 s to reach a velocity of 48 m/s south
Explanation:
Since the motion of the object is a uniformly accelerated motion, we can use the following suvat equation:
v = u + at
where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the object in this problem, choosing south as positive direction, we have:
u = 16 m/s
v = 48 m/s
[tex]a=4 m/s^2[/tex]
So we can solve the equation for t to find the time taken for the velocity to change from 16 m/s to 48 m/s:
[tex]t=\frac{v-u}{a}=\frac{48-16}{4}=8 s[/tex]
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