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17. Assuming that the reaction is a metathesis (double displacement) reaction; predict the products and write
the balanced molecular equation for the reaction of Pb(NO3)2 ing) with NaSO4 (ng) (16 pts.)
18. If the lead containing product from the reaction in question #17 is insoluble in water, and the other
product is soluble in water, what would the spectator tons be for the reaction in question #17? (6 pts)
19. Using the balanced molecular equation from #17: How many grams of Pb(NO3)2 would be needed to form
575g of the sodium containing product? (16pts.)

Respuesta :

cristisp93

17. Pb(NO₃)₂ (aq) + Na₂SO₄ (aq) → PbSO₄ (s) + 2 NaNO₃ (aq)

18. spectator ions: Na⁺ (aq) and NO₃⁻ (aq)

19. 1118.78 g of Pb(NO₃)₂

Explanation:

17. The balanced molecular equation:

Pb(NO₃)₂ (aq) + Na₂SO₄ (aq) → PbSO₄ (s) + 2 NaNO₃ (aq)

18. The balanced ionic equation:

Pb²⁺ (aq) + 2 NO₃⁻ (aq) + 2 Na⁺ (aq) + SO₄²⁻ (aq) → PbSO₄ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)

The spectator ions are the ions that will not participate at the chemical reaction and they will remain dissolved in the solution.

spectator ions: Na⁺ (aq) and NO₃⁻ (aq)

19. number of moles = mass / molecular weight

number of moles of NaNO₃ = 575 / 85 = 6.76 moles

Taking in account the balanced molecular equation we devise the following reasoning:

if        1 mole of Pb(NO₃)₂ produce 2 moles of NaNO₃

then  X moles of Pb(NO₃)₂ produce 6.76 moles of NaNO₃

X = (1 × 6.76) / 2 = 3.38 moles of Pb(NO₃)₂

mass = number of moles × molecular weight

mass of Pb(NO₃)₂ = 3.38 × 331 = 1118.78 g

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number of moles

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