Answer:
E =[tex]\frac{A(-q)}{d²}[/tex]
Explanation:
electric field magnitude, E is the intensity of electric force, F per charge, q applied.
thus, E = force per charge = F/q
there are two charges mention in the question. the charge -q placed on top of the plate is the source charge, while the charge, +q place at the bottom plate is the test charge. two charges is needed for an electric force to occur but for electric field calculation, the test charge, +q is used.
the application of coulomb law is used to determined electric force,
F=[ A *(+q)*(-q)]/d²
where,
A is the coulomb law constant = 9.0 x 10⁹ Nm²/C²
+q = test charge on bottom plate
-q = source charge
d = distance of separation between the top and bottom charge
applying the above equation in E
E = [ A *(+q)*(-q)]/d² DIVIDE q
E = [A(-q)]/d²
E =[tex]\frac{A(-q)}{d²}[/tex]
