ListenA person weighing 6.0 × 102 newtons rides an elevator upward at an average speed of 3.0 meters per second for 5.0 seconds. How much does this person’s gravitational potential energy increase as a result of this ride? a) 3.6 × 102 J b) 1.8 × 103 J c) 3.0 × 103 J d) 9.0 × 103 J.

Respuesta :

Answer:

(d) 9 × 10^{3] J

Explanation:

from the question we are given the following:

weight of the man = 6.0 × 10 ^ {2} N

average speed (v) = 3 m/s

time (t) = 3 s

potential energy (U) = ?

We can calculate the increase in potential energy of the man by applying the formula below

increase in potential energy = P₂ - P₁

where

  • P₁ is the initial potential energy
  • P₂ is the final potential energy
  • Potential energy = mass x acceleration due to gravity x height

From physic we know that weight = mass x acceleration due to gravity

  • We should take note that the distance in this case is also our height, and we can get it from the formula distance = velocity x time
  • Distance = 3 x 5 = 15 meters
  • Initial potential energy P₁ is zero because the person was initially in motion and potential energy is the energy at rest.

therefore

potential energy = 6.0 × 10 ^ {2} × 15 = 9 × 10^{3] J

The potential energy will be "9×10³ J".

Given values:

  • Weight of man = [tex]6.0\times 10^2 \ N[/tex]
  • Average speed = [tex]3 \ m/s[/tex]
  • Time = [tex]3 \ seconds[/tex]

We know,

→ [tex]Distance = Velocity\times Time[/tex]

By putting the values,

                  [tex]= 3\times 5[/tex]

                  [tex]= 15 \ m[/tex]

hence,

The potential energy,

= [tex]Mass\times Acceleration\times Height[/tex]

By substituting the values, we get

= [tex]6.0\times 10^2\times 15[/tex]

= [tex]9\times 10^3 \ J[/tex]

Thus the answer above i.e., "option d" is right.  

Learn more about potential energy here:

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