Answer:
T=1106.23 N*m
Explanation:
The torque exerted on the branch by the children is the force of both children make for distance so
∑F=Fx=0
[tex]F_{1}=m_{1}*g*cos(25)[/tex]
[tex]F_{2}=m_{2}*g*cos(25)[/tex]
[tex]T=F_{1}*d_{1}+F_{2}*d_{2}[/tex]
[tex]T=m_{1}*g*cos(25)d_{1}+m_{2}*g*cos(25)d_{2}[/tex]
[tex]T=g*cos(25)*[m_{1}*d_{1}+m_{2}*d_{2}][/tex]
Replacing numeric
[tex]T=9.8m/s^2*cos(25)*[48kg*1.4m+31kg*1.85m][/tex]
[tex]T=1106.23 N*m[/tex]