The sum of squares of numbers is: 13
Step-by-step explanation:
Let x and y be two numbers
Then,
Difference of the squares of the numbers will be:
[tex]x^2-y^2[/tex]
Product will be:
[tex]xy[/tex]
Given identity is:
[tex](x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2[/tex]
Given values are:
Difference of the squares of the numbers=[tex]x^2-y^2=5[/tex]
Product of numbers = xy = 6
Putting the values in the identity
[tex](x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169[/tex]
As we have to only find x^2+y^2
Taking square root on both sides
[tex]\sqrt{(x^2+y^2)^2}=\sqrt{169}\\x^2+y^2=13[/tex]
The sum of squares of numbers is: 13
Keywords: Identities
Learn more about identities at:
- brainly.com/question/8902155
- brainly.com/question/8955867
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