Answer:
The rate of formation of CO₂ is 11,7 M/s
Explanation:
The rate in a chemical reaction is defined as the change in concentration over the change in time
For the reaction:
2C₆H₁₄(l) + 19O₂(g) → 12CO₂(g) + 14H₂O(g)
The rate of dissapearance of C₆H₁₄ is 1,95 M/s
As 2 moles of C₆H₁₄ produce 12 moles of CO₂, the rate of formation of CO₂ will be 12/2 times faster than rate of disappearance, thus, rate of formation of CO₂ is:
1,95 M/s C₆H₁₄×[tex]\frac{12molCO_{2}}{2molC_{6}H_{14}}[/tex] = 11,7 M/s
I hope it helps!
