contestada

Cobalt-60 is an artificial radioisotope that is produced in a nuclear reactor and is used as a gamma-ray source in the treatment of certain types of cancer. If the wavelength of the gamma radiation from a cobalt-60 source is 1.00 × 10−3 nm, calculate the energy of a photon of this radiation.

Respuesta :

Answer:

[tex]1.9878\times 10^{-13}\ Joules[/tex]

Explanation:

c = Speed of light = [tex]3\times 10^8\ m/s[/tex]

[tex]\lambda[/tex] = Wavelength = [tex]1\times 10^{-3}\times 10^{-9}\ m[/tex]

h = Planck's Constant = [tex]6.626\times 10^{-34}\ m^2kg/s[/tex]

Energy

[tex]E=h\nu[/tex]

Frequency

[tex]\nu=\frac{c}{\lambda}\\\Rightarrow \nu=\frac{3\times 10^8}{1\times 10^{-3}\times 10^{-9}}\\\Rightarrow \nu=3\times 10^{20}\ Hz[/tex]

[tex]E=h\nu\\\Rightarrow E=6.626\times 10^{-34}\times 3\times 10^{20}\\\Rightarrow E=1.9878\times 10^{-13}\ J[/tex]

The energy of a photon is [tex]1.9878\times 10^{-13}\ Joules[/tex]