Answer:
a).[tex]Q_{h}=1.5x10^5J[/tex]
b).[tex]Q_{c}=13.2x10^3J[/tex]
Explanation:
a).
Using the law of thermodynamic and using to isovolumetric
ΔU=Qh
[tex]Q_{h}=\frac{W_{net}}{Efficiency}[/tex]
So to determine the internal energy knowing the work it do
[tex]Q_{h}=\frac{1.5x10^4J}{0.10}=1.5x10^5J[/tex]
b).
Efficiency is the work done in relation of the work apply in this case to produce heat so:
[tex]E=\frac{Q_{h}-Q_{c}}{Q_{h}}[/tex]
Solve to Qc
[tex]Q_{c}=Q_{h}*[1-E][/tex]
[tex]Q_{c}=1.5x10^4J*(1-0.10)[/tex]
[tex]Q_{c}=13.2x10^3J[/tex]