0.02 g of calcium carbonate (CaCO₃)
Explanation:
To solve the question we use the Avogadro's number using the following reasoning:
if 1 moles of calcium carbonate contains 6.022 × 10²³ units of calcium carbonate
then X moles of calcium carbonate contains 12.044 × 10²³ units of calcium carbonate
X = (1 × 12.044 × 10²³) / 6.022 × 10²³ = 2 moles of calcium carbonate
mass = number of moles × molecular weight
mass of calcium carbonate (CaCO₃) = 2 / 100 = 0.02 g
Learn more about:
Avogadro's number
https://brainly.com/question/13928106
#learnwithBrainly
