Answer: [tex]f(-64)=0[/tex]
[tex]f64)=0[/tex]
Step-by-step explanation:
The given function : [tex]f(x)=16-x^{2/3}[/tex]
When we substitute x= -64, we get
[tex]f(x)=16-(-64)^{2/3}[/tex]
Since , [tex]64=4\times4\times4=4^3[/tex]
So, [tex]-64=-4\times-4\times-4=-4^3[/tex]
That means [tex]f(-64)=16-(-64)^{2/3}=16-(-4^3)^{2/3}[/tex]
[tex]=16-(-4)^2=16-(-4\times-4)=16-16=0[/tex]
i.e. [tex]f(-64)=0[/tex]
Similarly, When we substitute x= 64, we get
[tex]f(x)=16-(64)^{2/3}[/tex]
Since , [tex]64=4\times4\times4=4^3[/tex]
That means [tex]f(64)=16-(64)^{2/3}=16-(4^3)^{2/3}[/tex]
[tex]=16-(4)^2=16-16=0[/tex]
i.e. [tex]f64)=0[/tex]
