Respuesta :
Answer:car L
Explanation:
Given
Three cars L ,M and N with mass [tex]m_L, m_M\ and m_N[/tex]
[tex]m_L> m_M > m_N[/tex]
let [tex]\mu [/tex]be the coefficient of kinetic friction
using [tex]v^2-u^2=2 as [/tex]
where v=final velocity
u=initial velocity
a=acceleration
s=distance moved
distance moved will be same as initial velocity is same and it is independent of mass
Work done by friction force is [tex]=\f_r\cdot s[/tex]
[tex]f_r_{L}=\mu m_Lg[/tex]
[tex]f_r_{M}=\mu m_Mg[/tex]
[tex]f_r_{N}=\mu m_Ng[/tex]
thus [tex]W_L=\mu m_Lg\cdot s[/tex]
[tex]W_M=\mu m_Mg\cdot s[/tex]
[tex]W_N=\mu m_Ng\cdot s[/tex]
as [tex]m_L[/tex] is greater therefore
[tex]W_L > W_M > W_N[/tex]
