Answer:
[tex]v = 14.23 m/s[/tex]
Explanation:
As per energy conservation we can say that during path 1. his initial total mechanical energy must be equal to final total mechanical energy
So we will have
[tex]mgH = \frac{1}{2}mv^2[/tex]
so we will have
[tex]m(9.81)(H) = \frac{1}{2}m(16.5)^2[/tex]
[tex]H = 13.88 m[/tex]
Now while he is moving on path 2. then again we can use energy conservation to find the speed
[tex]mg(H - y) = \frac{1}{2}mv^2[/tex]
[tex]m(9.81)(13.88 - 3.55) = \frac{1}{2}m v^2[/tex]
[tex]v = 14.23 m/s[/tex]
