Answer:
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
Step-by-step explanation:
In this problem we have a normal ditribution with mean of 4.0 in and standard deviation of 1.5 in.
The proportion of the trees that are expected to have diameters greater than 5 inches is equal to the probability of having a tree greater than 5 inches.
We can calculate the z value for x=5 in and then look up in a standard normal distribution table the probability of z.
[tex]z=\frac{x-\mu}{\sigma}=\frac{5-4}{1.5}=0.67[/tex]
[tex]P(x>5)=P(z>0.67)=0.25[/tex]
The proportion of trees greater than 5 inches is expected to be 0.25 of the total amount of trees.
