Answer:
7m/s
Explanation:
To solve this problem it is necessary to remember the concepts related to Centripedal force, normal force and frictional force.
The centripetal force is given by:
[tex]F_c = \frac{mv^2}{R}[/tex]
Where,
m=mass
v= velocity
R= Radius
On the other hand the Friction Force is given by,
[tex]F= \mu N[/tex]
In order for the Riders to maintain a vertical balance the force relative to the weight and friction must be equal, so
[tex]F_f = F_w[/tex]
[tex]\mu N = mg[/tex]
In the particular case of the movement the centripetal Force is equal to the normal force, thus, replacing
[tex]\mu \frac{mv^2}{R} = mg[/tex]
Re-arrange the velocity,
[tex]V_{min}= \sqrt{\frac{Rg}{\mu}}[/tex]
Replacing our values we have that,
[tex]V_{min} = \sqrt{\frac{3.6*9.8}{0.72}}[/tex]
[tex]V_ {min} = 7m/s[/tex]
