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The pressure of a sample of argon gas was increased from 3.50 ATM to8.34 ATM at constant temperature if the final volume of the argon sample was 18.3 L what was the initial volume of the argon sample assume ideal behavior

Respuesta :

nkirotedoreen46

Answer:

43.61 L

Explanation:

  • According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant absolute temperature.
  • Mathematically, [tex]P\alpha\frac{1}{V}[/tex]

                          [tex]P=\frac{k}{V}[/tex]

  • At varying volume and pressure

          k = P1V1 = P2V2

In this case we are given;

Initial pressure, P1 = 3.50 atm

Final pressure, P2 = 8.34 atm

Final volume, V2 = 18.3 L

We are required to calculate the initial volume, V1,

Rearranging the formula;

[tex]V1=\frac{P2V2}{P1}[/tex]

Therefore;

[tex]Initial volume=\frac{(8.34atm)(18.3L)}{3.50atm}[/tex]

                       [tex]=43.606[/tex]

Initial volume = 43.61 L

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