A student uses visible spectrophotometry to determine the concentration of CoCl2(aq) in a sample solution. First the student prepares a set of CoCl2 (aq) solutions of known concentration. Then the student uses a spectrophotometer to determine the absorbance of each of the standard solutions at a wavelength of 510 nm and constructs a standard curve. Finally, the student determines the absorbance of the sample of unknown concentration A wavelength of 510 nm corresponds to an approximate frequency of 6 x 10 s1.What is the approximate energy of one photon of this light? 9 x 1047 J A 3 x 1017 J 5 x 10 7 J 4 x 10 19 J

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Answer:

The approximate energy of one photon is [tex]E=4*10^{-19}J[/tex]

Explanation:

1. The energy of the photon can be related with the wave frequency, with the Planck-Einstein relation, that is:

[tex]E=h*f[/tex]

where h is the Planck constant and f is the frequency.

But the frequency f, can be expressed as:

[tex]f=\frac{c}{wavelentgth}[/tex]

where c is the speed of light.

So the Planck-Einstein relation can be written as:

[tex]E=\frac{h*c}{wavelength}[/tex]

2. Replacing values:

[tex]E=\frac{h*c}{wavelength}[/tex]

[tex]E=\frac{6.626*10^{-34}\frac{kg.m^{2}}{s}*3*10^{8}\frac{m}{s}}{5.1*10^{-7}m}[/tex]

[tex]E=4*10^{-19}\frac{kg.m^{2}}{s^{2}}[/tex]

[tex]E=4*10^{-19}J[/tex]

The energy of the light is  4 x 10^-19 J.

From the formula;

E = hc/λ

Note that;

h = Plank's constant = 6.6 × 10^-34 Js

c = speed of light = 3 × 10^8 m/s

λ = wavelength of light = 510 nm or 510 × 10^-9 m

Substituting values, we have;

E = 6.6 × 10^-34 Js ×  3 × 10^8 m/s/510 × 10^-9 m

E = 4 x 10^-19 J

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