Answer:
1.52905 seconds
4.58715 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
[tex]\mu[/tex] = Coefficient of friction = 0.4
g = Acceleration due to gravity = 9.81 m/s²
a = Acceleration = [tex]\mu g[/tex]
Equation of motion
[tex]v=u+at\\\Rightarrow t=\frac{v-u}{\mu g}\\\Rightarrow t=\frac{0-6}{-0.4\times 9.81}\\\Rightarrow t=1.52905\ s[/tex]
It will take 1.52905 seconds for the block to slow down
[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2\mu g}\\\Rightarrow s=\frac{0^2-6^2}{2\times 0.4\times -9.81}\\\Rightarrow s=4.58715\ m[/tex]
The block will travel 4.58715 m before it stops
