contestada

A softball, of mass m = 0.195 kg, is pitched at a speed v0 = 25.3 m/s. Due to air resistance, by the time it reaches home plate it has slowed by 11.9%. The distance between the plate and the pitcher is d = 13.7 m. Calculate the average force of air resistance, Fair, that is exerted on the ball during its movement from the pitcher to the plate.

Respuesta :

cjmejiab

Answer:

[tex]F = 1.0196N[/tex]

Explanation:

To give this problem a solution, it is necessary to use the kinematic equations. The equation that describes velocity as a function of acceleration is given by,

[tex]v^2 = v_0^2 -2ax[/tex]

Since there is a loss of 11.9%, in the final speed, that is to say that of the total speed, only 88.1% is the effective one, so

[tex](25.3*88.1\%)^2=25.3^2-2a(13.7)[/tex]

Re-arrange to find a,

[tex]a=-\frac{(25.3*88.1\%)^2-25.3^2}{2*13.7}[/tex]

[tex]a=5.229m/s^2[/tex]

Applying Newton's second law we have now that

[tex]F=ma[/tex]

[tex]F = (0.195)(5.229)[/tex]

[tex]F = 1.0196N[/tex]

The average force of air resistance should be F= 1.0196 N.

Calculation of the average force:

We know that

[tex]v^2 - v^20 - 2ax\\\\(25.3 \times 88.1\%)^2 = 25.3^2 - 2a(13.7)\\\\a = \frac{-25.3\times 88.1\%)^2-25.3^2}{2\times 13.7} \\\\a = 5.229 m/s^2[/tex]

Now

Here we applied the newton second law

So,

F = ma

= (0.195) (5.229)

= 1.0196 N

learn more about the force here: https://brainly.com/question/3398162

Otras preguntas