The solution is: x=2, y=-2
Step-by-step explanation:
Given equations are:
6x+2y=8 Eqn 1
12x+y=22 Eqn 2
Multiplying Eqn 1 by 2
[tex]2(6x+2y)=2(8)\\12x+4y=16[/tex] Eqn 3
Subtracting Equation 2 from eqn 3
[tex]12x+4y-(12x+y)=16-22\\12x+4y-12x-y=-6\\3y=-6\\Dividing\ both\ sides\ by\ 3\\\frac{3y}{3}=\frac{-6}{3}\\y=-2[/tex]
Putting y=-2 in eqn 2
[tex]12x-2=22\\Adding\ 2\ on\ both\ sides\\12x-2+2=22+2\\12x=24\\Dividing\ both\ sides\ by\ 12\\\frac{12x}{12} = \frac{24}{2}\\x=2[/tex]
The solution is: x=2, y=-2
Keywords: Linear equations, Elimination Method
Learn more about elimination method at:
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